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area and perimeter MCQ for SSC CGL

MCQ on Area and Perimeter for SSC CGL

Area of a rectangle is equal to the area of the circle whose radius is 21 cms. If the length and the breadth of the rectangle are in the ratio of 14 : 11 respectively, what is its perimeter ?

(a) 142 cms.

(b) 140 cms.

(c) 132 cms.

(d) 150 cms.

(e) None of these

Solution: (d)

Area of rectangle = Area of circle

\(\displaystyle \frac{{22}}{7}\times 21\times 21=1386sqcm\)

Let the length and breadth of rectangle be 14x and 11x cm respectively. Then

14x. 11x = 1386

\(\displaystyle \Rightarrow \)\(\displaystyle {{x}^{2}}=\frac{{1386}}{{14\times 11}}=9\)

\(\displaystyle \Rightarrow \)\(\displaystyle x=\sqrt{9}=3\)

Therefore, Perimeter of rectangle = 2 (14x + 11x)

= 50x = \(\displaystyle 50\times 3=150cm\)


A horse is tethered to a peg with a 14 meter long rope at the corner of a 40 meter long and 24 meter wide rectangular grass-field. What area of the field will the horse graze?

(a) \(\displaystyle 154{{m}^{2}}\)

(b) \(\displaystyle 308{{m}^{2}}\)

(c) \(\displaystyle 240{{m}^{2}}\)

(d) \(\displaystyle 480{{m}^{2}}\)

(e) None of these

Solution: (a)

Area and perimeter mcq for bank exams

Required area = \(\displaystyle \frac{1}{4}\times \pi {{R}^{2}}\)

\(\displaystyle \frac{1}{4}\times \frac{{22}}{7}\times 14\times 14=154sqmeter\)


The cost of fencing a circular plot at the rate of ₹ 15 per m is ₹ 3300. What will be the cost of flooring the plot at the rate of ₹ 100 per sq m?

(a) ₹ 385000

(b) ₹ 220000

(c) ₹ 350000

(d) Cannot be determined

(e) None of these

Solution: (a)

Circumference of circular plot = \(\displaystyle \frac{{3300}}{{15}}=220\)

\(\displaystyle \Rightarrow \) 2pr = 220

Therefore, \(\displaystyle r=\frac{{220}}{{2\times 22}}\times 7=\frac{{55\times 7}}{{11}}=35m\)

Total cost of flooring the plot = \(\displaystyle \pi {{r}^{2}}\times 100\)

\(\displaystyle \frac{{22}}{7}\times 35\times 35\times 100=385000\)


The length of a rectangular field is double its width. Inside the field there is a square-shaped pond 8 m long. If the area of the pond is 1/8 of the area of the field, what is the length of the field?

(a) 32 m

(b) 16 m

(c) 64 m

(d) 20 m

(e) None of these

Solution: (a)

Let width of the field = b m

\(\displaystyle \Rightarrow \) Length = 2 b m

Now, area of rectangular field = \(\displaystyle 2b\times b\)= \(\displaystyle 2{{b}^{2}}\)

Area of square shaped pond = \(\displaystyle 8\times 8=64\)

According to the question,

\(\displaystyle 64=\frac{1}{8}{{(2b)}^{2}}\Rightarrow {{b}^{2}}=64\times 4\Rightarrow b=16m\)

Therefore, Length of the field = \(\displaystyle 16\times 2=32m\)


The area of a right-angled triangle is two-thirds of the area of a rectangle. The base of the triangle is 80 percent of the breadth of the rectangle. If the perimeter of the rectangle is 200 cm, what is the height of the triangle?

(a) 20 cm

(b) 30 cm

(c) 15 cm

(d) Data inadequate

(e) None of these

Solution: (d)

Let the base and height of triangle, and length and breadth of rectangle be L and h, and \(\displaystyle {{L}_{1}}and{{b}_{1}}\) respectively. Then, \(\displaystyle \frac{1}{2}\times L\times h=\frac{2}{3}\times {{L}_{1}}\times {{b}_{1}}\) …(i)

\(\displaystyle L=\frac{4}{5}{{b}_{1}}\)  …(ii)

And \(\displaystyle {{L}_{1}}+{{b}_{1}}=100\) …(iii)

In the above we have three equations and four unknowns. Hence the value of ‘h’ can’t be determined.