number series questions for bank exams
Solve the number series questions given below:
3601 3602 1803 604 154 36 12
(a) 3602
(b) 1803
(c) 604
(d) 154
(e) 36
Solution: (d)
Given number series
\(\displaystyle 3601\div 1+1=3602\)
\(\displaystyle 3602\div 2+2=1803\)
\(\displaystyle 1803\div 3+3=604\)
\(\displaystyle 604\div 4+4=154\)
\(\displaystyle 154\div 5+5=36\)
\(\displaystyle 36\div 6+6=12\)
154 is written in place of 155.
4 12 42 196 1005 6066 42511
(a) 12
(b) 42
(c) 1005
(d) 196
(e) 6066
Solution: (b)
Given number series
\(\displaystyle 4\times 2+{{2}^{2}}=12\)
\(\displaystyle 12\times 3+{{3}^{2}}=42\)
\(\displaystyle 42\times 4+{{4}^{2}}=196\)
\(\displaystyle 196\times 5+{{5}^{2}}=1005\)
\(\displaystyle 1005\times 6+{{6}^{2}}=6066\)
\(\displaystyle 6066\times 7+{{7}^{2}}=42511\)
2 8 12 20 30 42 56
(a) 8
(b) 42
(c) 30
(d) 20
(e) 12
Solution: (a)
Given number series
\(\displaystyle 2+4=8\)
\(\displaystyle 8+6=12\)
\(\displaystyle 12+8=20\)
\(\displaystyle 20+10=30\)
\(\displaystyle 30+12=42\)
\(\displaystyle 42+14=56\)
32 16 24 65 210 945 5197.5
(a) 945
(b) 16
(c) 24
(d) 210
(e) 65
Solution: (e)
Given number series
\(\displaystyle 32\times 0.5=16\)
\(\displaystyle 16\times 1.5=24\)
\(\displaystyle 24\times 2.5=65\)
\(\displaystyle 65\times 3.5=210\)
\(\displaystyle 210\times 4.5=945\)
\(\displaystyle 945\times 5.5=5197.5\)
9050 5675 3478 2147 1418 1077 950
(a) 3478
(b) 1418
(c) 5675
(d) 2147
(e) 1077
Solution: (e)
Given number series
\(\displaystyle 9050-{{15}^{3}}=5675\)
\(\displaystyle 5675-{{13}^{3}}=3478\)
\(\displaystyle 3478-{{11}^{3}}=2147\)
\(\displaystyle 2147-{{9}^{3}}=1418\)
\(\displaystyle 1418-{{7}^{3}}=1077\)
\(\displaystyle 1077-{{5}^{3}}=950\)
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