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mcq on ratio and proportion for competitive exams like Bank, SSC, CDS, AFCAT, CAPF AC, CLAT, Police exams & State PSU exams.

MCQ on ratio and proportion

Solve the following MCQ on ratio and proportion:

The ratio of the monthly incomes of Sneha’s, Tina and Akruti is 95 : 110 : 116. If Sneha’s annual income is ₹ 3,42,000, what is Akruti’s annual income?

(a) ₹ 3,96,9000

(b) ₹ 5,63,500

(c) ₹ 4,17,600

(d) ₹ 3,88,000

(e) None of these

Solution: (c)

Let monthly income of Sneha, Tina and Akruti is 95x, 110x and 116x respectively

Annual income of Sneha = 12 \(\displaystyle \times \) 95x = 3,42,000

X = \(\displaystyle \frac{{342000}}{{95\times 12}}\)

Annual income of Akruti = 12 \(\displaystyle \times \) 116x

= \(\displaystyle 12\times 116\times \frac{{342000}}{{95\times 12}}\)

Akruti’s annual income = ₹ 4,17,600

Alternate method

Irrespective of monthly or annual income, we can solve the question as given below:

Sneha’s Income / Akruti Income = 95/116

342000 / Akruti Income=95/116

Akruti Income= (116 \(\displaystyle \times \) 342000)/95 = 417600

The ratio of Sita’s, Riya’s and Kunal’s monthly income is 84 : 76 : 89. If Riya’s annual income is ₹ 4,56,000, what is the sum of Sita’s and Kunal’s annual incomes? (In some cases monthly income is used while in others annual income is used.)

(a) ₹ 11,95,000

(b) ₹ 9,83,50

(c) ₹ 11,30,000

(d) ₹ 10,38,000

(e) None of these

Solution: (d)

Ratio of monthly income and ratio of annual income will be the same, ie 84 : 76 : 89

Therefore, Sum of Sita’s and Kunal’s annual income

= \(\displaystyle \frac{{456000}}{{76}}\times (84+89)=1038000\)

Alternate method

Let monthly income of Sita Riya and Kunal be 84k, 76k and 89k, respectively.
Given annual income of Riya = 456000
Therefore, Monthly income of Riya = 456000/12 = 38000
\(\displaystyle \Rightarrow \) 76k = 38000

\(\displaystyle \Rightarrow \) k = 500
So, the monthly income of Sita and Kunal = 84k + 89k = 173k
= 173 \(\displaystyle \times \) 500 = 86500
Therefore, annual income = 86500 \(\displaystyle \times \) 12 = ₹ 1038000

When the numerator and the denominator of a fraction are increased by 1 and 2 respectively, the fraction becomes \(\displaystyle \frac{2}{3}\)  and when the numerator and the denominator of the same fraction are increased by 2 and 3 respectively, the fraction becomes \(\displaystyle \frac{5}{7}\). What is the original fraction?

(a) \(\displaystyle \frac{5}{6}\)

(b) \(\displaystyle \frac{3}{4}\)

(c) \(\displaystyle \frac{3}{5}\)

(d) \(\displaystyle \frac{6}{7}\)

(e) None of these

Solution: (b)

\(\displaystyle \frac{{x+1}}{{y+2}}=\frac{2}{3}\)\(\displaystyle \Rightarrow 3x-2y=1\)

\(\displaystyle \frac{{x+2}}{{y+3}}=\frac{5}{7}\) \(\displaystyle \Rightarrow 7x-5y=1\)

Or, \(\displaystyle 3x-2y=7x-5y\)

\(\displaystyle \Rightarrow 3y=4x\)

\(\displaystyle \Rightarrow \)\(\displaystyle \frac{x}{y}=\frac{3}{4}\)

The respective ratio between the present age of Manisha and Deepali is 5 : X. Manisha is 9 years younger than Parineeta. Parineeta’s age after 9 years will be 33 years. The difference between Deepali’s and Manisha’s age is same as the present age of Parineeta. What will come in place of X?

(a) 23

(b) 39

(c) 15

(d) Cannot be determined

(e) None of these

Solution: (e)

According to the question

Present age of Parineeta = 33 – 9 = 24 years

Present age of Manisha = 24 – 9 = 15 years

Present age of Deepali = 24 + 15 = 39 years

Therefore, 5 : X = 15 : 39

\(\displaystyle \Rightarrow \)x = \(\displaystyle \frac{{5\times 39}}{{15}}=13\)

Alternate method

Present age of Parineeta is 33 – 9 = 24 years

Age of Manisha = 24 – 9 = 15 years

But from the given information, difference Mamsha and Deepali’s age is 24 years

Deepali’s Age =15+24=39 years

Thus, Deepali’s present age is 39 years.

Now, as the ratio of Manisha’s age and Deepali’s age is , so…

Manisha / Deepali=5 / x

15/39=5/x

15x=95

x=195/15

Therefore, x=13

So, the value of X is 13

The ratio between Gloria’s and Sara’s present ages is 4 : 7 respectively. Two years ago the ratio between their ages was 1 : 2 respectively. What will be Sara’s age three years hence ?

(a) 17 years

(b) 14 years

(c) 11 years

(d) 8 years

(e) None of these

Solution: (a)

Let Gloria’s and Sara’s present ages be 4x and 7x years respectively.

Two years ago, \(\displaystyle \frac{{4x-2}}{{7x-2}}=\frac{1}{2}\)

\(\displaystyle \Rightarrow \) 8x – 4 = 7x – 2

\(\displaystyle \Rightarrow \) x= 2

Therefore, Sara’s age three years hence = 7x + 3 = 17 years

Alternate method

Let the present age of Gloria and Sara be A and B respectively

It is given that, \(\displaystyle \frac{A}{B}=\frac{4}{7}\)———–(1)

Two Years back Gloria age will be A – 2 and Sara age will be B – 2 and which is given that

\(\displaystyle \frac{{A-2}}{{B-2}}=\frac{1}{2}\)————(2)

Solving the two equations we get B=14 years, so three years hence age of Sara will be=14+3=17 years