The ratio of the ages of A and B seven years ago was 3 : 4 respectively. The ratio of their ages nine years from now will be 7 : 8 respectively. What is B’s age at present ?
Therefore present age of B = 4x + 7 =4 x 4 + 7 = 28
A certain amount was to be distributed among A, B and C in the ratio 2 :3 :4 respectively, but was erroneously distributed in the ratio 7:2:5 respectively. As a result of this, B got ₹ 40 less. What is the amount ?
(a) ₹ 210/-
(b) ₹ 270/-
(c) ₹ 230/-
(d) ₹ 280/-
(e) None of these
Solution: (a)
Let amount of B = ₹ x
B’s Share without error = \(\displaystyle \frac{{B’sratio}}{{totalratio}}=totalamount\)
x = \(\displaystyle \frac{3}{9}\times totalamount\) …(1)
B’s share after error = \(\displaystyle \frac{{B’snewratio}}{{tota\ln ewratio}}\times totalamount\)
M, N, O and P divided ₹ 44352 among themselves. M took 3/8 th of the money, N took 1/6 th of the remaining amount and rest was divided among O and P in the ratio of 3 : 4 respectively. How much did O get as his share?
A sum of ₹ 221 is divided among X, Y and Z such that X gets ₹ 52 more than Y. Y gets ₹ 26 more than Z. The ratio of the shares of X, Y and Z respectively is:
(a) 9 : 5 : 3
(b) 9 : 3 : 5
(c) 5 : 9 : 3
(d) 10 : 6 : 5
(e) None of these
Solution: (a)
x = y + 52
y = z + 26 or z = y – 26
and x + y + z = 221
(y + 52) + y + (y – 26) = 221
3y + 26 = 221
3y = 221 – 26 = 195
\(\displaystyle y=m\frac{{195}}{3}=65\)
x = y + 52 = 65 + 52 = 117
z = y – 26 = 65 – 26 = 39
x : y : z = 117 : 65 : 39 = 9 : 5 : 3
In two vessels A and B, there is mixture of milk and water. The ratio of milk and water in these vessels is 5 : 2 and 8 : 5 respectively. In what ratio these mixtures be mixed together so that the ratio of milk and water in the new mixture becomes 9 : 4 ?
(a) 7 : 2
(b) 2 : 7
(c) 3 : 5
(d) 5 : 3
(e) 7 : 9
Solution: (a)
Let C.P. of milk per litre be ₹ 1
Milk in 1 litre of A = \(\displaystyle \frac{5}{7}litre\)
Milk in 1 litre of B = \(\displaystyle \frac{8}{{13}}litre\)
Required ratio = \(\displaystyle \frac{1}{{13}}:\frac{2}{{91}}\) = 7:2
