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MCQ on Speed Time and Distance with answers and detailed explanations for competitive exams like Bank, SSC, Railways, Insurance, CDS, AFCAT, CAPF AC, CLAT, Police exams & State PSU exams

Yesterday Priti typed an essay of 5000 words at the speed of 60 words per minute. Today she typed the same essay faster and her speed was 15% more than yesterday. What is the approximate difference in the time she took to type yesterday and the time she took to type today?

(a) 20 minutes

(b) 30 minutes

(c) 10 minutes

(d) 40 minutes

(e) 1 hour


Solution: (c)
Priti’s second day speed of typing = \(\displaystyle \frac{{60\times 115}}{{100}}=69wordsper\min\)
\(\displaystyle \Rightarrow \)Required difference in time = \(\displaystyle (\frac{{5000}}{{60}}-\frac{{5000}}{{69}})\min\)
=\(\displaystyle 5000(\frac{{69-60}}{{60\times 69}})\min\)
=\(\displaystyle \frac{{5000\times 9}}{{60\times 69}}=10\min\)

A truck covers a certain distance in 12 hours at the speed of 70 km/hr. What is, the average speed of a car which travels a distance of 120 km more than the truck in the same time?

(a) 56km./hr.

(b) 75km./hr.

(c) 82km./hr.

(d) 78km./hr


Solution: (e)

Distance covered by truck in 12 hours = \(\displaystyle speed\times time=70\times 12=840\) km

Distance covered by car in 12 hours = (840 + 120 =) 960 km

Average speed of car = \(\displaystyle \frac{{distance}}{{time}}\)

=\(\displaystyle \left( {\frac{{960}}{{12}}} \right)=80km/hr\)

A man riding a bicycle completes one lap of a square field along its perimeter at the speed of 43.2 km/hr in 1 minute 20 seconds. What is the area of the field?

(a) 52900 sq m

(b) 57600 sq m

(c) 48400 sq m

(d) Cannot be determined

(e) None of these


Solution: (b)

43.2 km/hr = \(\displaystyle 43.2\times \frac{5}{{18}}=12m/s\)

Total distance covered = \(\displaystyle 12\times 80=960\) m

Perimeter of the square = 960 m

Side of the square = \(\displaystyle \frac{{960m}}{4}=240m\) Area = \(\displaystyle {{(240)}^{2}}=57600sqm\)

A man riding a bicycle completes one lap of a circular field along its circumference at the speed of 14.4 km/hr in 1 minute 28 seconds. What is the area of the field?

(a) 7958 sq mt

(b) 9856 sq mt

(c) 8842 sq mt

(d) Cannot be determined

(e) None of these

Solution: (b)

14.4 km/hr = \(\displaystyle (14.4\times \frac{5}{8})4m/s\)

Total time = (60 + 28) = 88 s

Total distance = \(\displaystyle 4\times 88=352\) m

Circumference = 352 m

or, \(\displaystyle 2\pi r\) = 352 m

or, \(\displaystyle 2\times \frac{{22}}{7}\times r=352m\)

or,  \(\displaystyle r=\frac{{352\times 7}}{{22\times 2}}=56m\)

Now, area of circle = \(\displaystyle \pi {{r}^{2}}=\frac{{22}}{7}\times 56\times 56\)

= \(\displaystyle 9856{{m}^{2}}\)

A 240 metre long train crosses a platform twice its length in 2 minutes. What is the speed of the train?

(a) 8 m/s

(b) 4 m/s

(c) 6 m/s

(d) Cannot be determined

(e) None of these

Solution: (c)

Length of train = 240 m

Length of platform = \(\displaystyle 240\times 2=480m\)

Speed of train = \(\displaystyle \frac{{lengthoftrain+lengthofplatform}}{{time}}\)

\(\displaystyle \frac{{240+480}}{{2\times 60}}=\frac{{720}}{{120}}=6m/s\)