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Speed time distance questions with solutions

MCQ on Time and Distance questions with solutions

A car driver leaves Bangalore at 8.30 A.M. and expects to reach a place 300 km from Bangalore at 12.30 P.M. At 10.30 he finds that he has covered only 40% of the distance. By how much he has to increase the speed of the car in order to keep up his schedule?

(a) 45 km/hr

(b) 40 km/hr

(d) 30 km/hr

(e) 50 km/hr

Answer: (d)

Distance covered by car in 2 hours = \(\displaystyle \frac{{300\times 40}}{{100}}=120km\)

Remaining distance = 300 – 120 = 180 km

Remaining time = 4 – 2 = 2 hours

Required speed = \(\displaystyle \frac{{180}}{2}=90kmph\)

Original speed of car = \(\displaystyle \frac{{120}}{2}=60kmph\)

A man is walking at a speed of 10 kmph. After every km, he takes a rest for 5 minutes. How much time will he take to cover a distance of 5 km?

(a) 60 minutes

(b) 50 minutes

(d) 70 minutes

(e) 80 minutes

Answer: (b)

Time taken in covering 5 Km = \(\displaystyle \frac{5}{{10}}=\frac{1}{2}hour=30\min utes\)

That person will take rest for four times.

Required time = \(\displaystyle (30+4\times 5)\min utes=50\min utes\)

A journey takes 4 hours 30 minutes at a speed of 60 km/hr. If the speed is 15 m/s, then the journey will take

(a) 5 hours

(b) 5 hours 30 minutes

(d) 6 hours 15 minutes

(e) 6 hours 45 minutes

Time taken in covering 5 Km = \(\displaystyle \frac{5}{{10}}=\frac{1}{2}hour=30\min utes\)

Answer: (a)

60 kmph = \(\displaystyle (\frac{{60\times 5}}{{18}})m/\sec =\frac{{50}}{3}m/\sec \)

\(\displaystyle Speed\infty \frac{1}{{Time}}\)

\(\displaystyle {{S}_{1}}\times {{T}_{1}}={{S}_{2}}\times {{T}_{2}}\)

\(\displaystyle \frac{{50}}{3}\times \frac{9}{2}=15\times {{T}_{2}}\)

\(\displaystyle 75=15\times {{T}_{2}}\)

A farmer travelled a distance of 61 km in 9 hours. He travelled partly on foot at the rate 4 kmph and partly on bicycle at the rate 9 kmph. The distance travelled on foot is

(a) 16 km

(b) 14 km

(d) 15

(e) 18 km

Answer: (a)

Time taken in covering 5 Km = \(\displaystyle \frac{5}{{10}}=\frac{1}{2}hour=30\min utes\)

Distance travelled by farmer on foot = x km (let)

Distance covered by cycling = (61– x) km.

Time = \(\displaystyle \frac{{dis\tan ce}}{{speed}}\)

According to the question

\(\displaystyle \frac{x}{4}+\frac{{61-x}}{9}=9\)

\(\displaystyle \frac{{9x+61\times 4-4x}}{{9\times 4}}=9\)

5x + 244 = \(\displaystyle 9\times 9\times 4=324\)

5x = 324 – 244 = 80

\(\displaystyle x=\frac{{80}}{5}=16km\)

A man cycles at the speed of 8km/hr and reaches office at 11 am and when he cycles at the speed of 12 km/hr he reaches office at 9 am. At what speed should he cycle so that he reaches his office at 10 am?

(a) 9.6 kmph.

(b) 10 kmph.

(d) Cannot be determined

(e) None of these

Answer: (a)

Distance of the office = x km.

Difference of time = 2 hours

\(\displaystyle \frac{x}{8}-\frac{x}{{12}}=2\)

\(\displaystyle \frac{{3x-2x}}{{24}}=2\)

\(\displaystyle \frac{x}{{24}}=2\Rightarrow x=48km\)

Time taken at the speed of 8 kmph = \(\displaystyle \frac{{48}}{8}=6hours\)

Required time to reach the office at 10 a.m. i.e., in 5 hours = \(\displaystyle (\frac{{48}}{5})kmph=9.6kmph\)

We hope that the MCQ on Time and Distance that are provided on this page has boosted your preparation for competitive exams. Our comprehensive collection of Time, Speed, and Distance MCQs are prepared by experts looking into the latest trends of the exams. This page is designed to help candidates excel in topics like speed time and distance questions, it has all the topics covered as per the syllabus of the competitive exams. By practicing time speed and distance questions with answers, aspirants can know what the current status of their preparation is. Time speed and distance questions with solutions can help improve your preparation and know new shortcut tricks that will save time during the exam.

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