Amit and Sujit together can complete an assignment of data entry in five days. Sujit’s speed is 80% of Amit’s speed and the total key depressions in the assignment are 5,76,000. What is Amit’s speed in key depressions per hour if they work for 8 hours a day?
(a) 4800
(b) 6400
(c) 8000
(d) 7200
(e) None of these
Solution: (c)
Ratio of the work done by Sujit and Amit = 80 : 100 = 4 : 5
Total key depressions done by Amit = \(\displaystyle \frac{5}{9}\times 576000=320000\)
Amit’s speed in key depressions per hour = \(\displaystyle \frac{{320000}}{{8\times 5}}=8000\)
Alternate method:
Let Amit’s speed of key depressions per hour be X.
So, Sumit’s speed of key depressions is 80% of X.
In total, the number of key depressions per hour by both of them is 1.8 X
The total number of key depressions in a day by both of them together is 1.8 \(\displaystyle \times \)8 X= 14.4 X
This equals 576000/5 = 115200.
So, 14.4 \(\displaystyle \times \) X = 115200
or, X = 115200/14.4 = 8000
An aeroplane flies with an average speed of 756 km/h. A helicopter takes 48 hours to cover twice the distance covered by aeroplane in 9 h. How much distance will the helicopter cover in 18 h? (Assuming that flights are non-stop and moving with uniform speed.)
(a) 5010 km
(b) 4875 km
(c) 5760 km
(d) 5103 km
(e) None of these
Solution: (d)
Distance covered by the aeroplane in 9 h = \(\displaystyle 9\times 756=6804km\)
Speed of helicopter = \(\displaystyle \frac{{2\times 6804}}{{48}}=283.5km/h\)
Distance covered by helicopter in 18 h = \(\displaystyle 283.5\times 18=5103km\)
Wheels of diameters 7 cm and 14 cm start rolling simultaneously from X and Y, which are 1980 cm apart, towards each other in opposite directions. Both of them make the same number of revolutions per second. If both of them meet after 10 seconds, the speed of the smaller wheel is:
An aeroplane takes off 30 minutes later than the scheduled time and in order to reach its destination 1500 km away in time, it has to increase its speed by 250 km/h from its usual speed. Find its usual speed.
A farmer travelled a distance of 61 km in 9 hrs. He travelled partly on foot at the rate of 4 km/hr and partly on bicycle at the rate of 9 km/hr. The distance travelled on foot is
(a) 17 km
(b) 16 km
(c) 15km
(d) 14 km
(e) None of these
Solution: (b)
Then, distance travelled by bicycle = (61 –x) km
So, \(\displaystyle \frac{x}{4}+\frac{{61-x}}{9}=9\)