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mcq on time and distance

The average speed of a train is 3 times the average speed of a car. The car covers a distance of 520 kms in 8 hours. How much distance will the train cover in 13 hours ?

(a) 2553 km

(b) 2585 km

(c) 2355 km

(d) 2535 km

(e) None of these

Solution: (d)

Speed of car = \(\displaystyle \frac{{dis\tan ce}}{{time}}\)

\(\displaystyle \frac{{520}}{8}=65kmph\)

Speed of train = 65 × 3 = 195 kmph

Distance covered by train in 13 hours = 13 × 195 = 2535 km

Yesterday Shweta completed 300 units of work at the rate of 15 units per minute. Today she completed the same units of work but her speed was 40% faster than yesterday. What is the approximate difference in the time she took to complete the work yesterday and the time she took today ?

(a) 16 minutes

(b) 26 minutes

(c) 46 minutes

(d) 36 minutes

(e) 6 minutes

Solution: (e)

Shweta’s initial speed = 15 units per minute

Shweta’s new speed = \(\displaystyle \frac{{15\times 140}}{{100}}=21units/\min ute\)

Difference in time

\(\displaystyle (\frac{{300}}{{15}}-\frac{{300}}{{21}})\min utes\)

\(\displaystyle 300(\frac{1}{{15}}-\frac{1}{{21}})\min utes\)

\(\displaystyle 300(\frac{{7-5}}{{105}})\min utes\)

\(\displaystyle \frac{{300\times 2}}{{105}}\min utes=6\min utes\)

Neeraj, Manoj and Geeta start running around a circular stadium and complete one round in 10 seconds, 6 seconds and 14 seconds respectively. In how much time will they meet again at the starting point?

(a) 3 minutes 30 seconds

(b) 2 minutes 28 seconds

(c) 4 minutes 45 seconds

(d) 1 minute 40 seconds

(e) None of these

Solution: (a)

In this type of questions use LCM (Least Common Multiple) Method

Required time = LCM of 10, 6 and 14 seconds

= 210 seconds = 210/60 minutes = 3 minutes 30 seconds.

(Since 1 minute= 60 seconds)

Meghana 3.36 km. in four weeks by walking an equal distance each day. How many meters does she walk each day?

(a) 100 m

(b) 60 m

(c) 140 m

(d) 120 m

(e) None of these

Solution: (d)

Distance walked by Meghna = (3.36 × 1000) metres.

Four weeks = \(\displaystyle 4\times 7=28\) days

\(\displaystyle \$ Distance covered in 1 day = \)latex \displaystyle \frac{{3.36\times 1000}}{{4\times 7}}=120m$

A truck covers a distance of 256 km at the speed of 32 km/hr. What is the average speed of a car which travels a distance of 160 km more than the truck in the same time?

(a) 46 km/h

(b) 52 km/h

(c) 49 km/h

(d) 64 km/h

(e) None of these

Solution: (b)

Time taken by the truck = \(\displaystyle \frac{{256}}{{32}}=8hr\)

Distance covered by the car = (256 + 160 =) 416 km

Time = 8 hr

Speed of the car = \(\displaystyle \left( {\frac{{416}}{6}} \right)=52\) km/h