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mcq on time and distance for competitive exams

A truck covers a distance of 330 km at the speed of 30 km/hr. What is the average speed of a car which travels a distance of 110 km more than the truck in the same time?

(a) 42 km/hr

(b) 48 km/hr

(c) 39 km/hr

(d) 38 km/hr

(e) None of these

Solution: (e)

Total time taken by truck = \(\displaystyle \frac{{330}}{{30}}=11hrs\)

New distance = 330 + 110 = 440 km

Average speed of car = \(\displaystyle \frac{{440}}{{11}}=40km/hr\)

Anu walks 2.31 km in three weeks by walking an equal distance each day. How many metres does she walk each day?

(a) 110 m

(b) 90 m

(c) 140 m

(d) 120 m

(e) None of these

Solution: (a)

2.31 km = \(\displaystyle 2.31\times 1000=2310\) m

Total number of days = \(\displaystyle 3\times 7=21\)

Therefore,  Distance covered by Anu each day

\(\displaystyle \frac{{2310}}{{21}}=110m\)

A 360-metre-long train cross a platform in 120 seconds. What is the speed of the train?

(a) 3 m/s

(b) 5 m/s

(c) 4.5 m/s

(d) Cannot be determined

(e) None of these

Solution: (d)

It can’t be determined because the length of the platform is not given.

A truck covers a distance of 640 km in 10 hr. A car covers the same distance in 8 hr. What is the ratio of the speed of the truck to that of the car?

(a) 3 : 4

(b) 1 : 2

(c) 5 : 6

(d) 6 : 7

(e) None of these

Solution: (e)

Speed of the truck = \(\displaystyle \frac{{640}}{{10}}=64km/hr\)

Speed of the car = \(\displaystyle \frac{{640}}{8}=80km/hr\)

Ratio = \(\displaystyle \frac{{64}}{{80}}=\frac{4}{5}=4:5\)

A man riding a bicycle  completes one lap of a circular field along its circumference at the speed of 79.2 km/hr in 2 minutes 40 seconds. What is the area of the field?

(a) 985600 sq metre

(b) 848500  sq metre

(c) 795600  sq metre

(d) Cannot be determined

(e) None of these

Solution: (a)

79.2 km/hr = \(\displaystyle 79.2\times \frac{5}{{18}}=22m/s\)

2 min 40 sec =  \(\displaystyle 2\times 60+40=120+40=160\sec \)

Circumference of circular field = \(\displaystyle speed\times time=22\times 160=3520m\)

Radius of circular field (r) = \(\displaystyle \frac{{circumference}}{{2\pi }}\)

\(\displaystyle \frac{{3520\times 7}}{{2\times 22}}=560m\)

Area of circular field = \(\displaystyle \pi {{r}^{2}}=\frac{{22}}{7}\times {{(560)}^{2}}\) \(\displaystyle \frac{{22}}{7}\times 560\times 560=985600{{m}^{2}}\)