Rankers Hub

time speed and distance ssc cgl questions with solutions

The distance between two cities A and B is 330 km. A train starts from A at 8 a.m. and travels towards B at 60 km/hr. Another train starts from B at 9 a.m. and travels towards A at 75 km/hr. At what time do they meet?

(a) 10:30 am

(b) 10:45 am

(c) 11 am

(d) 11:25 am

(e) None of these

Answer: (c)

Suppose they meet x hrs after 8 a.m.

Then, (Distance moved by first in x hrs) + [Distance moved by second in (x – 1)hrs] = 330

60x + 75(x – 1) = 330

x = 3

So, they meet at (8 + 3), i.e. 11 a.m

A man rows 750m in 775 seconds against the stream and returns in \(\displaystyle 7\frac{1}{2}\) minutes. What is rowing speed in still water?

(a) 4.7 km/hr

(b) 4 km/hr

(c) 3.5 km/hr

(d) 6 km/hr

(e) None of these

Answer: (a)

Speed upstream ‘b’ = 750m / 775 sec = 30/31 m/sec

Speed downstream ‘a’ = 750 m/ (15/2) minutes [1 min=60 sec] a = 750m/450 sec = 5/3 m/sec speed in still water

\(\displaystyle \frac{1}{2}(a+b)\)

\(\displaystyle \frac{1}{2}(\frac{{750}}{{450}}+\frac{{750}}{{675}})m/\sec \)

\(\displaystyle \frac{1}{2}(\frac{{750}}{{450}}+\frac{{750}}{{675}})\times \frac{{18}}{5}km/hr\)

\(\displaystyle \frac{1}{2}(\frac{5}{3}+\frac{{30}}{{31}})\times \frac{{18}}{5}km/hr\)

= 4.7 km/hr

A train travels at a speed of 40 km/h and another train at a speed of 20 m/s. What is the ratio of speed of the first train to that of the second train?

(a) 2 : 1

(b) 5 : 9

(c) 5 : 3

(d) 9 : 5

(e) None of these

Answer: (b)

Speed of a train = 40 km/h

\(\displaystyle 40\times \frac{5}{{18}}m/s\)

Speed of another train = 20 m/s

 Required ratio =  \(\displaystyle \frac{{speedoffirsttrain}}{{speedof\sec ondtrain}}\)

\(\displaystyle \frac{{40\times \frac{5}{{10}}}}{{20}}=\frac{{2\times 5}}{{18}}=\frac{{10}}{{18}}=\frac{5}{9}or5:9\)

Two trains of length 110 m and 90 m are running on parallel lines in the same direction with a speed of 45km/h and 50 km/h respectively. In what time will they pass other?

(a) 136 s

(b) 138 s

(c) 142 s

(d) 146 s

(e) None of these

Answer: (e)

Relative speed = (50 – 45) km/h = 5 km/hr

\(\displaystyle 5\times \frac{5}{{18}}m/s=\frac{{25}}{{18}}m/\sec \)

According to question

\(\displaystyle \frac{{25}}{{18}}=\frac{{110+90}}{t}\)

\(\displaystyle t=\frac{{200\times 18}}{{25}}=144s\)

A man rows 25 km downstream and 20 km upstream taking 5 h each time. What is the velocity of the current?

(a) 1 km/h

(b) 2.5 km/h

(c) 3.5 km/h

(d) 4.5 km/h

(e) None of these

Answer: (e)

Speed downstream = \(\displaystyle \frac{{25}}{5}km/h=5km/h\)

Speed upstream = \(\displaystyle \frac{{25}}{5}km/h=4km/h\)

Velocity of the current = \(\displaystyle \frac{1}{2}(5-4)km/h=0.5km/h\)