MCQ on Speed Time and Distance | Page 9 of 13 | Qiestions and Answers Rankers Hub

time speed and distance practice questions

Practice questions on time speed and distance

The speed of a truck is \(\displaystyle \frac{1}{3}\)rd the speed of a train. The train covers 1230 km is 5 hours. What is the speed of the truck?

(a) 85 km./hr

(b) 82 km./hr

(d) 87 km./hr

(e) None of these

Answer: (b)

Speed of the train = \(\displaystyle (\frac{{1230}}{5})=246km/hr\)

Speed of the truck = \(\displaystyle (\frac{1}{3}\times 246)=82km/hr\)

Ashok left from place A (towards place B) at 8 am and Rahul left from place B (towards place A) at 10 am. The distance between place A and place B is 637 km. If Ashok and Rahul are travelling at a uniform speed of 39 km/h and 47 km/h respectively, at what time will they meet?

(a) 5 : 30 pm

(b) 4 : 30 pm

(d) 4 : 00 pm

(e) 3 : 30 pm

Answer: (b)

speed time and distance MCQ for Competitive exams

Time taken = Total distance to cover / Relative Velocity = 559/86 = 6.5 h

Meeting time = 10 am + 6.5 h. = 4 : 30 pm.

A man can row 30 km upstream and 44 km downstream in 10 hrs. Also, he can row 40 km upstream and 55 km downstream in 13 hrs. Find the speed of the man in still water.

(a) 5 km/hr

(b) 8 km/hr

(d) 12 km/hr

(e) 8.5 km/hr

Answer: (b)

Let upstream speed = x, downstream speed = y km/h

Then, \(\displaystyle \frac{{30}}{x}+\frac{{44}}{y}=10and\frac{{40}}{x}+\frac{{55}}{y}=13\)

Put \(\displaystyle \frac{1}{x}=a,\frac{1}{y}=b\)

Solve the equations.

\(\displaystyle a=\frac{1}{5},b=\frac{1}{{11}}\)

So, x = 5, y = 11

Speed in still water = \(\displaystyle (\frac{{5+11}}{2})=8\)

A truck covers a distance of 376 km at a certain speed in 8 hours. How much time would a car take at an average speed which is 18 kmph more than that of the speed of the truck to cover a distance which is 14 km more than that travelled by the truck ?

(a) 6 hours

(b) 5 hours

(d) 8 hours

(e) 7.5 hours

Answer: (a)

Speed of the truck = \(\displaystyle \frac{{Dis\tan ce}}{{Time}}=\frac{{376}}{8}=47kmph\)

Now, speed of car = (speed of truck + 18) kmph = (47 + 18) = 65 kmph

Distance travelled by car = 376 + 14 = 390 km

Time taken by car = \(\displaystyle \frac{{Dis\tan ce}}{{Speed}}=\frac{{390}}{{65}}=6hours\)

Two trains are moving in opposite directions at 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

(a) 58 sec

(b) 50 sec

(d) 56 sec

(e) None of the

Answer: (c)

Relative speed = \(\displaystyle \frac{{alllengths}}{{time}}\)

\(\displaystyle [60+90]=\frac{{1.10+0.9}}{{time}}\)

time = \(\displaystyle \frac{2}{{150}}=\frac{1}{{75}}h\)

1 hour = 3600 sec

\(\displaystyle \frac{1}{{75}}hr=?\)

\(\displaystyle ?=\frac{{3600}}{{75}}=48\sec \)

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time speed and distance practice questions

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