Now 80% of 190 = \(\displaystyle \frac{{190\times 80}}{{100}}=152\)
In an examination it is required to get 65% of the aggregate marks to pass, A student gets 847 marks and is declared failed by 10% marks. What are the maximumaggregate marks a student can get?
(a) 1450
(b) 1640
(c) 1500
(d) Cannot be determined
(e) None of these
Solution: (e)
Let maximum marks = x
Student got 55% x = 847
Therefore, x = \(\displaystyle x=\frac{{847\times 100}}{{55}}=1540\)
Last year there were 610 boys in a school. The number decreased by 20 percent this year. How many girls are there in the school if the number of girls is 175 percent of the total number of boys in the school this year?
(a) 854
(b) 848
(c) 798
(d) 782
(e) None of these
Solution: (a)
No. of boys, last year = 610
20% of 610 = 122 No. of boys, current year = 610 – 122 = 488
A student was awarded certain marks in an examination. However, after re-evaluation, his marks were reduced by 40% of the marks that were originally awarded to him so that the new score now became 96. How many marks did the student lose after re-evaluation?
(a) 58
(b) 68
(c) 63
(d) 56
(e) 64
Solution: (e)
Let initial marks of student = x
After re-evaluation marks reduced by 40% of x
New score = 60% of x = 96
= \(\displaystyle \frac{{60}}{{100}}\times x=96\)
x=\(\displaystyle x=\frac{{96\times 100}}{{60}}\)
x=160
Marks lose = 160 – 96 = 64
What should come in place of the question mark so that it satisfies equality of the equation ?
32% of 750 < ?
(a) 23% of 600
(b) 46% of 207
(c) 98% of 250
(d) 75% of 320
(e) None of these
Solution: (c)
32% of 750=\(\displaystyle \frac{{32\times 750}}{{100}}=240\)
23% of 600 =\(\displaystyle \frac{{23\times 600}}{{100}}=138\)
46% of 207 =\(\displaystyle \frac{{46\times 207}}{{100}}=95.22\)
98% of 250 =\(\displaystyle \frac{{98\times 250}}{{100}}=245\)
Mathew scored 42 marks in Biology, 51 marks in Chemistry, 58 marks Mathematics, 35 marks in Physics and 48 marks in English. The maximum marks a student can score in each subject are 60. How much overall percentage did Mathew get in this exam?
(a) 76
(b) 82
(c) 68
(d) 78
(e) None of these
Solution: (d)
Total maximum marks of 5 subjects = 60 × 5 = 300
Total marks of Mathew = 42 + 51 + 58 + 35 + 48 = 234
% of Marks = \(\displaystyle \frac{{234}}{{300}}\times 100=78\%\)
Sum of three consecutive numbers is 2262. What is 41 % of the highest number?
(a) 301.51
(b) 303.14
(c) 308.73
(d) 306.35
(e) 309.55
Answer is (e)
Let the numbers are x, x + 1, x + 2
Sum of three consecutive numbers = 2262
x + x + 1 + x + 2 = 2262
3x + 3 = 2262
3x = 2259
x = 753
Number are 753, 754, 755
Therefore, 41% of 755 = 309.55
The respective ratio of salaries of A and B is 8 : 7. If the salary of B increases by 20% and the salary of A increases by 21%, the new ratio becomes 96 : 77 respectively. What is A’s salary?
Here x is cancelled. So, salary of A can’t determined.
A merchant bought some goods worth Rs. 6000 and sold half of them at 12% profit. At what profit percent should he sell the remaining goods to make and overall profit of 18%?
(a) 24
(b) 28
(c) 18
(d) 20
(e) 26
Answer is (a)
Profit on all the goods = 18% of 6000 = ₹ 1080
Profit on half of the goods = 12% of 3000 = ₹ 360
Therefore, the profit on remaining half of the objects
Prema decided to donate 15% of her salary to an orphanage. On the day of donation she changed her mind and donated ₹ 1,896 which was 80% of what she had decided earlier. How much is Prerna’s salary?
