Rankers Hub

time and work mcq ssc

Objective Questions Time and Work

Answer the Time and Work MCQ:

A can do a piece of work in 4 hours; B and C can do it in 3 hours. A and C can do it in 2 hours. How long will B alone take to do it ?

(a) 10 hours

(b) 12 hours

(c) 8 hours

(d) 24 hours

(e) 28 hours

Answer for this MCQ Time and Work is (b)

A’s 1 hour’s work = \(\displaystyle \frac{1}{4}\)

(B + C)’s 1 hour’s work = \(\displaystyle \frac{1}{3}\)

(A + C)’s 1 hour’s work = \(\displaystyle \frac{1}{2}\)

C’s 1 hour’s work = \(\displaystyle \frac{1}{2}-\frac{1}{4}=\frac{{2-1}}{4}=\frac{1}{4}\)

and B’s 1 hour’s work = \(\displaystyle \frac{1}{3}-\frac{1}{4}=\frac{{4-3}}{{12}}=\frac{1}{{12}}\)

Hence, B alone can do the work in 12 hours.

A and B together can do a piece of work in 10 days. A alone can do it in 30 days. The time in which B alone can do it is

(a) 10 days

(b) 12 days

(c) 15 days

(d) 20 days

(e) 25 days

Answer for this MCQ Time and Work is (c)

(A + B)’s 1 day’s work = \(\displaystyle \frac{1}{{10}}\)

A’s 1 day’s work = \(\displaystyle \frac{1}{{30}}\)

B’s 1 day’s work = \(\displaystyle \frac{1}{{10}}-\frac{1}{{30}}=\frac{{3-1}}{{30}}=\frac{2}{{30}}=\frac{1}{{15}}\)

Hence, B, alone can complete the work in 15 days.

Alternate Method :

Time taken by B = \(\displaystyle \frac{{30\times 10}}{{30-10}}=15days\)

A alone can complete a work in 12 days. A and B together can complete it in 8 days. How long will B alone take to complete the work ?

(a) 24 days

(b) 18 days

(c) 16 days

(d) 20 days

(e) 25 days

Answer for this MCQ Time and Work is (a)

A’s 1 day’s work = \(\displaystyle \frac{1}{{12}}\)

(A+B)’s 1 day’s work = \(\displaystyle \frac{1}{{8}}\)

B’s 1 day’s work = \(\displaystyle \frac{1}{8}-\frac{1}{{12}}=\frac{{3-2}}{{24}}=\frac{1}{{24}}\)

Therefore, B alone can do the work in 24 days.

Alternate Method :

Time taken by B = \(\displaystyle \frac{{12\times 8}}{{12-8}}=24days\)

A work can be completed by P and Q in 12 days, Q and R in 15 days, R and P in 20 days. In how many days P alone can finish the work?

(a) 10 days

(b) 20 days

(c) 30 days

(d) 60 days

(e) 70 days

Answer for this MCQ Time and Work is (c)

(P + Q)’s 1 day’s work = \(\displaystyle \frac{1}{{12}}\) …(i)

(Q + R)’s 1 day’s work = \(\displaystyle \frac{1}{{15}}\) …(ii)

(R + P)’s 1 day’s work = \(\displaystyle \frac{1}{{20}}\) …(iii)

Adding all three equations,

2 (P + Q + R)’s 1 day’s work = \(\displaystyle \frac{1}{{12}}+\frac{1}{{15}}+\frac{1}{{20}}=\frac{{5+4+3}}{{60}}=\frac{{12}}{{60}}=\frac{1}{5}\)

 (P + Q + R)’s 1 day’s work = \(\displaystyle \frac{1}{{10}}\) …(iv)

P’s 1 day’s work = \(\displaystyle \frac{1}{{10}}-\frac{1}{{15}}=\frac{{3-2}}{{30}}=\frac{1}{{30}}\)

Therefore, P alone will complete the work in 30 days.

A and B together can do a piece of work in 5 days and A alone can do it in 8 days. B alone can do the same piece of work in

(a) \(\displaystyle 11\frac{1}{3}days\)

(b) \(\displaystyle 12\frac{3}{5}days\)

(c) \(\displaystyle 13\frac{1}{3}days\)

(d) \(\displaystyle 16\frac{4}{5}days\)

(e) \(\displaystyle 16\frac{2}{3}days\)

Answer for this MCQ Time and Work is (c)

(A + B)’s 1 day’s work = \(\displaystyle \frac{1}{5}\)

A’s 1 day’s work = \(\displaystyle \frac{1}{8}\)

B’s 1 day’s work = \(\displaystyle \frac{1}{5}-\frac{1}{8}=\frac{{8-5}}{{40}}=\frac{3}{{40}}\)

B alone will complete the work in \(\displaystyle \frac{{40}}{3}=13\frac{1}{2}days\)

Alternate Method:

Time taken by B = \(\displaystyle \frac{{5\times 8}}{{8-5}}=\frac{{40}}{3}=13\frac{1}{3}days\)

A, B and C together can complete a piece of work in 30 minutes. A and B together can complete the same work in 50 minutes. C alone can complete the work in

(a) 60 minutes

(b) 75 minutes

(c) 80 minutes

(d) 150 minutes

(e) 120 minutes

Answer for this MCQ Time and Work is (b)

Work done by (A + B + C) in 1 minute = \(\displaystyle \frac{1}{{30}}\)

Work done by (A + B) in 1 minute = \(\displaystyle \frac{1}{{50}}\)

Work done by C alone in 1 minute = \(\displaystyle \frac{1}{{30}}-\frac{1}{{50}}=\frac{{5-3}}{{150}}=\frac{2}{{150}}=\frac{1}{{75}}\)

Therefore, C alone will complete the work in 75 minutes.

Alternate Method:

C alone can do in = \(\displaystyle \frac{{xy}}{{x-y}}=\frac{{50\times 30}}{{50-30}}=75\min utes\)

A, B and C individually can do a work in 10 days, 12 days and 15 days respectively. If they start working together, then the number of days required to finish the work is

(a) 16 days

(b) 8 days

(c) 4 days

(d) 2 days

(e) 6 days

Answer for this MCQ Time and Work is (c)

Work done by A, B and C in 1 day

\(\displaystyle \frac{1}{{10}}+\frac{1}{{12}}+\frac{1}{{15}}=\frac{{6+5+4}}{{60}}=\frac{{15}}{{60}}=\frac{1}{4}\)

Required time = 4 days

Alternate Method:

Time Taken = \(\displaystyle \frac{{xyz}}{{xy+yz+zx}}\)

\(\displaystyle \frac{{10\times 12\times 15}}{{10\times 12+12\times 15+15\times 10}}\)

\(\displaystyle \frac{{1800}}{{120+180+150}}\)

\(\displaystyle \frac{{1800}}{{450}}=4days\)

Ronald and Elan are working on an Assignment. Ronald takes 6 hours to type 32 pages on a computer, while Elan takes 5 hours to type 40 pages. How much time will they take working together on two different computers to type an assignment of 110 pages ?

(a) 7 hrs. 30 min.

(b) 8 hrs.

(c) 8 hrs. 15 min.

(d) 8 hrs. 25 min.

(e) 8 hrs. 45 min.

Answer for this MCQ Time and Work is (c)

Ronald’s 1 hour’s work = \(\displaystyle \frac{{32}}{6}=\frac{{16}}{3}pages\)

[Pages typed in 6 hrs. = 32

Therefore, pages typed in 1 hr = \(\displaystyle \frac{{32}}{6}\)]

Elan’s 1 hour’s work = 8 pages

1 hour’s work of the both = \(\displaystyle \frac{{16}}{3}+8=\frac{{40}}{3}pages\)

Required time = \(\displaystyle \frac{{110\times 3}}{{40}}=\frac{{33}}{4}hours\)

= 8 hours 15 minutes